By Laszlo Lovasz

A examine of the way complexity questions in computing have interaction with classical arithmetic within the numerical research of concerns in set of rules layout. Algorithmic designers involved in linear and nonlinear combinatorial optimization will locate this quantity in particular beneficial.

Two algorithms are studied intimately: the ellipsoid technique and the simultaneous diophantine approximation strategy. even supposing either have been constructed to review, on a theoretical point, the feasibility of computing a few really expert difficulties in polynomial time, they seem to have sensible functions. The publication first describes use of the simultaneous diophantine technique to enhance refined rounding strategies. Then a version is defined to compute top and decrease bounds on a number of measures of convex our bodies. Use of the 2 algorithms is introduced jointly via the writer in a examine of polyhedra with rational vertices. The ebook closes with a few purposes of the implications to combinatorial optimization.

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Diophantine approximation and rounding. Let QI, . . , an G Q . The problem of finding a good simultaneous approximation of these numbers can be transformed into a short lattice vector problem as follows. Given 0 < e < 1 and Q > 0 , consider the matrix and the lattice £(A) generated by its columns. , p n +i) T 6 Z n+1 . Suppose that 6 ^ 0 but ||6 | < . Then clearly pn+i ^ 0 . We may assume without loss of generality that pn+i < 0 . Let q = —pn+i , then we have and AN ALGORITHMIC THEORY 29 or Thus, a "short" vector in C(A) yields a "good" simultaneous approximation of o t i , .

It may be easier to see the geometric content of (ii) if we remark that a vector c such that \\c\\ = 1 and is just a unit vector such that the rotational cone with vertex in y , axis parallel to c and semi-angle arctg(n + 1) (which is quite close to Tr/2) is disjoint from K . With the c in the statement, it suffices to find a congruent cone with vertex closer to y than c and disjoint from K ; and this is what we shall achieve. We assume, to make the main idea behind the algorithm more clear, that we have a strong membership oracle; with a weak oracle, it would take some additional work but no essentially new idea to carry out the calculations.

Qn 1 , not all 0, such that and Remark. n are uniformly bounded. The details of this are left to the reader as an exercise (note that the lattice generated by A is not full-dimensional). 9). 4) Theorem. Given a, {3 e Qn and e, Q > 0 , we can achieve in polynomial time one of the following: (i) find p 6 Zn and q e 7. such that 0 < q < Q and (ii) find u G Zn such that Remark. Conclusions (i) and (ii) are not mutually exclusive, but is easy to see that if (i) has a solution in p and q then for all u £ Z n , one has Hence if (ii) has a solution for some e and Q then (i) has no solution with = £ .